x^2-29x+540=0

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Solution for x^2-29x+540=0 equation:


Simplifying
x2 + -29x + 540 = 0

Reorder the terms:
540 + -29x + x2 = 0

Solving
540 + -29x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-540' to each side of the equation.
540 + -29x + -540 + x2 = 0 + -540

Reorder the terms:
540 + -540 + -29x + x2 = 0 + -540

Combine like terms: 540 + -540 = 0
0 + -29x + x2 = 0 + -540
-29x + x2 = 0 + -540

Combine like terms: 0 + -540 = -540
-29x + x2 = -540

The x term is -29x.  Take half its coefficient (-14.5).
Square it (210.25) and add it to both sides.

Add '210.25' to each side of the equation.
-29x + 210.25 + x2 = -540 + 210.25

Reorder the terms:
210.25 + -29x + x2 = -540 + 210.25

Combine like terms: -540 + 210.25 = -329.75
210.25 + -29x + x2 = -329.75

Factor a perfect square on the left side:
(x + -14.5)(x + -14.5) = -329.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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